Party A needs to do it for 20 days first, and Party B needs to do the rest (1-20/30)* 120=40 (days).
Suppose the daily cost of a. B is x per person. Ten thousand yuan RMB
(X+Y)*24= 120 then X+Y=5.
20X+40Y= 1 10 is 2X+4Y= 1 1.
X=9/2 30X= 135 can be obtained.
Y= 1/2 120Y=60
Party A needs 1.35 million yuan, and Party B needs 600,000 yuan. 2. There is a shortage of 44 square meters for the first-class worker to paint the wall, and seven second-class workers to paint six walls at the same time 14 square meters. Each first-class worker draws more 10 square meter every day than the second-class worker. What is the area of each wall? If the area of each wall is x square meters, the area of each first-class worker painting the wall every day is (4X-44)/3m2, and that of each second-class worker painting the wall every day is (6x+14)/7m2 [(4x-44)/3]-[(6x+14)/. = 21028x-308-18x-42 = 21010x = 560x = 56 The area of each wall is 56 square meters. 3. A group of lawn mowers cut two lawns, the big one is twice as big as the small one, and they all cut the grass in the big one in the morning. According to the custom, a day's work is counted from morning till night, half in the morning and half in the afternoon. ) If the number of people is X, each person mows grass every day 1 unit, the grass area is Y, and the grass area is 2Y..
Mowing in the morning x *1/2 = x/2;
Lawn mowing in the afternoon (x/2) * (1/2) = x/4;
Mowing in the afternoon (x/2) * (1/2) = x/4;
The next day, a person mowing grass is1*1=1;
Then: X/2+X/4=2y.
X/4+ 1=y
The solution is X=8.
In other words, the total number of lawn mowers is 8.