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This is a math problem.
1。 If the number of A is 60% more than B, then the number of B is less than A..

60%÷( 1+60%)=37.5%

Think of b as the unit 1.

Then a is 1+60%

B is 60% less than A, accounting for 60% of A/(1+60%) = 37.5%.

2。 Removing the percent sign is equivalent to the original 100 times.

49.5÷( 100- 1)=50%

A: This figure used to be 50%.

3. The minimum qualified rate is 84%, 50*84%=42.

The production efficiency of a garment factory is X sets/day.

10x+ 150 = 3÷ 1× 10x×0.4

x=75

75×3÷ 1× 10=2250 (set)

A: There are 2,250 school uniforms.