So the number of moles of sodium hydroxide is V*d*W/40.
So the molar concentration of sodium hydroxide is d*W/40.
After dilution, the concentration becomes d*W*(V-m)/(V*40).
When diluted, the concentration becomes d * w * [(v-m)/v] 2/40.
The molar number of sodium hydroxide is d * w * (v-m) 2/(v * 40).
Neutralization requires the same molar amount of hydrochloric acid.
The mass of hydrochloric acid is d * w * (v-m) 2 * 36.5/(v * 40).
The mass of hydrochloric acid solution is d * w (v-m) 2 * 36.5/4v.
2. The first three are composed of the same elements, but not the same substance.
The latter three are different generic names of the same substance.
20 18 Henan college entrance examination mathematical simulation questions (including answers)
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