1. If x= 1 is the solution of the equation ax+ 1=2, then a=( 1).

2. When x=( 1), the values of algebraic expressions 4x+2 and 3x-9 are opposite to each other.

3. If -3x 2A- 1+6 = 0 is a linear equation, then a=( 1) and the solution of the equation is x=(2).

During the National Day, shops have seasonal discounts. Xiaojun bought a sportswear at a 20% discount, saving 16 yuan, so he actually spent (64) yuan on this dress.

5. There are 27 people working in place A and 9 people working in place B/KLOC-0. Now 20 people are transferred to support, so the number of people in place A is twice that in place B, and they should be transferred to place A (17).

6、7

Second, solve the equation.

(1) 3y-4 (1of y-2) = 5.

The first question: Remove the brackets and get (3y-4y+2=5).

Move the item to get (3y-4y=5-2)

Merge similar items to get (-y=3), so y=-3.

(2)2 x- 1=3 x- 1

Divide by the denominator to get (3x-3=2x-2).

Get by moving items (3x-2x=-2+3)

Combining similar projects, we get (x= 1).

Third, the application problem.

1, set (x yuan per notebook, then x+2 yuan per pen)

Equation:15x+10 (x+2) =100-5.

Solve this equation and you get (x=3), so each notebook has a 3 yuan and each pen has a 5 yuan.

2.( 1) Suppose two cars meet x hours after departure.

Equation: (95+85)x=36

Solve this equation to get (x=0. 2) So 0. See you in two hours.

(2) Assume that the distance between the two cars is 6 kilometers after Y time.

Equation: (95+85)y=36-6.

Solve this equation to get (y= 1/6), so after 1/6 hours, the two cars are 6 kilometers apart.

3. If there are X students in Class B, then the number of students in Class A (104-x) is104 */kloc-0 =1040. If both classes are more than 5 1, which does not meet the question, then Class B is less than 50.

12x+ 10( 104-x)= 1 136

x=48

So there are 48 students in Class B and 56 students in Class A..

(2) If two classes are a group, each class will be 8 yuan, saving Y yuan.

104*8+y= 1 136

y=304