According to the triangle side length formula A +b -2abcosC=c (ABBC is three sides and ABBC is the corresponding angle of ABBC), the diagonal of the parallelogram is equally divided.

So 14 square+19 square -2* 14* 19*cos angle AOD=24 square, formula1; 14 square+19 square-2 *14 *19 * cos (180 AOD)=CD square, formula 2.

2 * 14 * 19 * COS angle AOD=- 19 is given by the formula 1,

And cos (180-α) =-cos α.

In formula 2, CD square = 14 square+19 square-2 *14 *19 * cos (180-aod) =14 square+/kloc.

Perimeter = 48+2 √ ~ 538