Current location - Training Enrollment Network - Mathematics courses - In 2009, Changde City took the senior high school entrance examination in mathematics testNo. 16 and its answer.
In 2009, Changde City took the senior high school entrance examination in mathematics testNo. 16 and its answer.
There is actually another explanation: 1. First judge the total score of 5 games. Because C was the referee three times, A and B played three games. The title said that A and B appeared four times each, so A and C got 1 field, and B and C got 1 field, making a total of five games.

2. Since the probability of A and B is the same, A can be used to represent A and B, and B can be used to represent C. Asking the loser in the second game is actually asking the referee in the third game. I assume that A (A or B) is used to represent the referee of the third game, that is, the loser of the second game is A (A or B), then the third game can be expressed as A B A, and you can infer the situation of other games accordingly. Anyway, according to this situation, it is absolutely impossible for C to be a referee three times.

To sum up, the referee in the third game is B, that is, C, that is, the loser in the second game is C.

I hope it helps you!