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Average problem of fourth grade mathematics
The number of girls is half that of boys.

So the average weight of all students is equal to the average weight of two boys and one girl =(4 1*2+35)/3=39.

Sum of four numbers = 14*4=56

The sum of three large numbers is 15*3=45, and the decimal is 56-45 = 1 1.

The sum of three decimal places is 38, and the large number =56-38= 18.

So the sum of the middle two numbers =45+38-56=27.

The second largest number is odd, and the middle two numbers are >; 1 1 and

So 27 can only be divided into 15+ 12, and the second largest odd number is 15.

The average is 120/6=20, which is a continuous odd number, so 15, 17,19,2123,25.

(38*50-55-69)/(50-2)=37

The first four digits and the last four digits are only repeated once by the fourth digit.

Therefore, the fourth number =30*4+60*4-49*7= 17.