Given two vectors a=(x, y, z) b=( 1, 2, 3), then point a times the modulus of b = the modulus of a * * cos =x+2y+3z= root number 14.

And the modulus of A = root number (x 2+y 2+z 2) =1b = root number 14 is brought into it, and then we can know that COS =1; Then the included angle between A and B is 0, that is, A and B are parallel, so the vector A of x:y:z= 1:2:3 can be written as a=(x, 2x, 3x); X2+4x2+9x2 =1find14x+y+z = 6x = 6 times the radical number, and114.