When x< is 0,
If a & gt=0, the minimum value of f(x) is f (0) = a 2.
If a
When x> is 0,
The minimum value of f(x) is f( 1)=a+2.
From the meaning of the title, you must first have a & gt=0.
And then a 2.
The solution is-1
Together, it is
Option d