There is a condition, in fact, that is, the output of 80%I meter = the output of II meter.

(1) Purchase price of rice II = 1.6× output of rice I/output of rice II = 1.6/0.8=2.

(2) Assuming that the yield of rice II is Y and the yield of rice I is X, there is 2.2y- 1.6x= 1040.

X/y= 1/0.8=5/4。

So x=6500 y=5200.

Finally, find the value of x+y = 1 1700.