1.ABC has two copies each, and there is a method of n = c (6,2) * c (4,2) * c (2,2), that is, A takes two copies, of the remaining four books, B takes two copies and gives the remaining two to C;
2. In the case of 1 Let A be a 1a2, B be a3a4, C be a5a6, A, B, C have such different corresponding ways (ABC, ACB, BAC, BCA, CBA) * * A (3 3,3) = 6.