(x+4)/3-(2y-3)/5=2(2)

Solution: (x+3)/2=7-(y+5)/3.

Let (y+5)/3=k, then y=3k-5.

Then (x+3)/2=7-k, then x= 1 1-2k.

(x+4)/3-(2y-3)/5=2

( 1 1-2k+4)/3-(6k- 10-3)/5 =( 15-2k)/3-(6k- 13)/5 = 2

5( 15-2k)-3(6k- 13)= 30

k=3

x= 1 1-2k=5

y=3k-5=4

The solution of the equation is

x=5

y=4