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Knowledge classification of book number operation in the sixth grade of primary school mathematics
1

Number of copies × number of copies = total number of copies

Total copies/number of copies = number of copies

Total copies/number of copies = number of copies

2

1 multiple × multiple = multiple

Multiply1Multiply = Multiply

Multiply/Multiply = 1 Multiply

three

Speed × time = distance

Distance/speed = time

Distance/time = speed

four

Unit price × quantity = total price

Total price/unit price = quantity

Total price ÷ quantity = unit price

five

Work efficiency × working hours = total workload.

Total amount of work ÷ work efficiency = working hours

Total workload ÷ working time = working efficiency

six

Appendix+Appendix = Sum

And-one addend = another addend

seven

Negative-negative = difference

Negative difference = negative

Difference+Minus = Minus

eight

Factor × factor = product

Product ÷ One factor = another factor

nine

Dividend = quotient

Dividend = divisor

Quotient × Divider = Divider

Calculation formula of mathematical graphics in primary schools

1

square

C circumference

S region

length of a side

Perimeter = side length ×4

C=4a

Area = side length × side length

S=a×a

2

cube

Five: volume

A: Edge length

Surface area = side length × side length ×6

S table =a×a×6

Volume = side length × side length × side length

V=a×a×a

three

rectangle

C circumference

S region

length of a side

Circumference = (length+width) ×2

C=2(a+b)

Area = length × width

S=ab

four

Cubic

Five: volume

Student: Area

A: Dragon.

B:

extensive

tall

(1) Surface area (L× W+L× H+W× H) ×2

S=2(ab+ah+bh)

(2) Volume = length × width × height

V=abh

five

triangle

S region

Adidas

H height

Area = bottom × height ÷2

s=ah÷2

Height of triangle = area

× 2 base

Triangle base = area

× 2 Current height

six

parallelogram

S region

Adidas

H height

Area = bottom × height

S = ah

seven

trapeziform

S region

A shangdi

Shadi

H height

Area = (upper bottom+lower bottom) × height ÷2

s =(a+b)× 1

h \u 2

eight

Round; circular

S region

C circumference

D= diameter

R= radius

(1) circumference = diameter ×∏=2×∏× radius

C=∏d=2∏r

(2) area = radius × radius×∈

nine

cylinder

Five: volume

tall

s; Jianping

R: bottom radius

C: perimeter of bottom surface

(1) lateral area = bottom circumference × height.

(2) Surface area = lateral area+bottom area ×2

(3) Volume = bottom area × height

(4) Volume = lateral area ÷2× radius.

10

cone

Five: volume

tall

s; Jianping

R: bottom radius

Volume = bottom area × height ÷3

Total number ÷ Total number of copies = average value

Formula of sum and difference problem

(sum+difference) ÷ 2 = large number

(sum and difference) ÷ 2 = decimal

And folding problems.

Sum \ (multiple-1) = decimal

Decimal × multiple = large number

(or

And-decimal = large number)

Difference problem

Difference ÷ (multiple-1) = decimal

Decimal × multiple = large number

(or

Decimal+difference = large number)

Tree planting problem

1

The problem of planting trees on non-closed lines can be divided into the following three situations:

(1) If trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes+1 = total length-1.

Total length = plant spacing × (number of plants-1)

Plant spacing = total length ÷ (number of plants-1)

2 If you want to plant trees at one end of the unclosed line and not at the other end, then:

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

(3) If no trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes-1 = total length-1.

Total length = plant spacing × (number of plants+1)

Plant spacing = total length ÷ (number of plants+1)

2

The quantitative relationship of planting trees on the closed line is as follows

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants

Plant spacing = total length/number of plants

The question of profit and loss

(Profit+Loss) ÷ Difference between two distributions = number of shares participating in distribution.

(Big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution.

(big loss-small loss) ÷ The difference between two distributions = the number of shares participating in the distribution.

encounter a problem

Meeting distance = speed × meeting time

Meeting time = meeting distance/speed and

Speed sum = meeting distance ÷ meeting time

Catch up with the problem

Catch-up distance = speed difference× catch-up time

Catch-up time = catch-up distance ÷ speed difference

Speed difference = catching distance ÷ catching time

Tap water problem

Downstream velocity = still water velocity+current velocity

Countercurrent velocity = still water velocity-current velocity

Still water velocity = (downstream velocity+countercurrent velocity) ÷2

Water velocity = (downstream velocity-countercurrent velocity) ÷2

Concentration problem

Solute weight+solvent weight = solution weight.

The weight of solute/solution × 100% = concentration.

Solution weight × concentration = solute weight

Solute weight-concentration = solution weight.

Profit and discount problem

Profit = selling price-cost

Profit rate = profit/cost × 100% = (selling price/cost-1) × 100%.

Up and down amount = principal × up and down percentage

Discount = actual selling price ÷ original selling price× 1 00% (discount <1)

Interest = principal × interest rate× time

After-tax interest = principal × interest rate × time × (1-20%)

This is for primary school 1-6 grade, adopt it! !