∫OB bisects the angle COD, so the angle BOD = 1/2 * 45 = 22.5.

∠∠AOD =∠AOB+∠BOD

So ∠ AOD = 60+22.5 = 82.5.

Let the angle BOC be x, then

60 X = 3(45 X)

X=37.5

Angle AOD= Angle AOC+ Angle DOC=(60-37.5)+45. . Too lazy to forget.

m-45