∫OB bisects the angle COD, so the angle BOD = 1/2 * 45 = 22.5.
∠∠AOD =∠AOB+∠BOD
So ∠ AOD = 60+22.5 = 82.5.
Let the angle BOC be x, then
60 X = 3(45 X)
X=37.5
Angle AOD= Angle AOC+ Angle DOC=(60-37.5)+45. . Too lazy to forget.
m-45