1, y = the square of a-4a+3
The square of = (a-2) is-1, so y is greater than or equal to-1.
X=2+2b-b squared
The square of = 3-(b- 1) is less than or equal to 3.
Therefore, it can be concluded that the m- intersection p is greater than or equal to-1 and less than or equal to 3.
2, by x +(p+2)x+ 1 square =0, then
The square of [x+(p+2)/2] = the square of (p+2)/2-1
At this time, it can be concluded that the square of (p+2)/2- 1 is greater than or equal to 0, and p is greater than or equal to 2 or less than and so on.
Yu 6
You can subtract (p+2)/2 from [(p squared +4p)/4] under the formula x = radical sign.
If the intersection of a and R+ is not equal to an empty set, then x should be greater than 0.
When p is greater than or equal to 2, the formula does not meet the requirements, while when p is less than or equal to -6, the formula meets the requirements.
So the range of p is less than or equal to -6.
3. Judging from the meaning of the question,
The square of Y = (x-a) in set A-the square of A+3b can be obtained, and y is greater than or equal to the square of A+3b.
In set B, the square of y =-(x-a)+a+7b can be obtained, and y is less than or equal to the square of a+7b.
Multiply by the square of -a+3b = 2.
The square of a+7b = 8
Solution, a =+ 1 or-1.
b= 1