1, y = the square of a-4a+3

The square of = (a-2) is-1, so y is greater than or equal to-1.

X=2+2b-b squared

The square of = 3-(b- 1) is less than or equal to 3.

Therefore, it can be concluded that the m- intersection p is greater than or equal to-1 and less than or equal to 3.

2, by x +(p+2)x+ 1 square =0, then

The square of [x+(p+2)/2] = the square of (p+2)/2-1

At this time, it can be concluded that the square of (p+2)/2- 1 is greater than or equal to 0, and p is greater than or equal to 2 or less than and so on.

Yu 6

You can subtract (p+2)/2 from [(p squared +4p)/4] under the formula x = radical sign.

If the intersection of a and R+ is not equal to an empty set, then x should be greater than 0.

When p is greater than or equal to 2, the formula does not meet the requirements, while when p is less than or equal to -6, the formula meets the requirements.

So the range of p is less than or equal to -6.

3. Judging from the meaning of the question,

The square of Y = (x-a) in set A-the square of A+3b can be obtained, and y is greater than or equal to the square of A+3b.

In set B, the square of y =-(x-a)+a+7b can be obtained, and y is less than or equal to the square of a+7b.

Multiply by the square of -a+3b = 2.

The square of a+7b = 8

Solution, a =+ 1 or-1.

b= 1