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The tenth problem of the third compulsory course of mathematics in senior one.
πx/4-π/2=0 x=2 A (2，0) OA=(2，0) πx/4-π/2=π/4 πx/4= 3π/4 x=3 B (3， 1)

OB =(3， 1)o b-OA = OB+AO = AO+OB = AB =(3， 1)-(2，0)=( 1， 1)(o b-OA)OB = 3× 1+ 1× 1 = 3+ 1 = 4

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