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Mathematical solution 78
7. The above picture can be divided into two parts.

The upper part is divided into a semicircle with a diameter of 6, and the lower part is a sector with a radius of 6 and a central angle of 60 degrees.

So shadow area = sector area+semicircle area-semicircle area = sector area

=60/360πr2= 1/6*π*6*6=6π

8. The coordinate of point P is (x, 0).

The distance from point p to AB is

d = │(√3/3)x+√3│/√(√3/3)? +(- 1)? )=│(√3/3)x+√3│/(2√3/3)

If the circle p intersects a straight line, d < 1, i.e.

│(√3/3)x+√3│/(2√3/3)< 1

│(√3/3)x+√3│