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Mathematical spoon
Equality.

Solution: Let the original red wine and white wine each have X, and one spoon is Y. ..

Then the content of liquor in red wine is y/(x x y), and the content of red wine is x/(x x y).

Spoon a spoonful into liquor, then the red wine in this spoon is xy/(x 1Y), and the content of red wine in liquor is:

[xy/(x ten y)]÷x=y/(x ten y)

So equal