1050/30=35

Explain that 1050 is 500+550 (total workload) and 30 is 10+20 (total speed), so the shortest time limit must be to exert the maximum limit to complete the work. No one can't complete the total workload in one day, so just list it directly.

the second question

Because the topic says that the working days of changing jobs A and B are the same (that is, it happened in advance, and I thought too much at first ... I thought about what happened after half a day of job hopping, and the length was different), so I can directly change jobs for X days.

Area A has 500-20x

Area B has 550- 10x.

So 10

Since Party A has at least 250 pieces in A 'an, that is, it works normally for at least 25 days, that is, the limit shift1016 5438+02131415 days * *. ...