Solution:
A's work efficiency =1/6-110 =115.
It takes1(115) =15 days to complete.
2. For a job, Party A will complete it in 5 hours 1, and Party B will complete half of the remaining tasks in 6 hours. Finally, Party A and Party B cooperated. How long will it take to finish the rest of the work?
Solution: A's work efficiency =( 1/4)/5= 1/20.
B completed (1-1/4) ×1/2 = 3/8.
Party B's work efficiency = (3/8)/6 =116.
The sum of the work efficiency of Party A and Party B =1/20+116 = 9/80.
At this point, 1- 1/4-3/8=3/8 has not been completed.
It takes (3/8)/(9/80)= 10/3 hours.
3. The construction team will complete a project in 30 days, with 18 people first and 12 days to complete 3/ 1 of the project. How many people will be added if it is completed on time?
Solution: Everyone's work efficiency = (1/3)/(12×18) =1/648.
It takes 30- 12= 18 days to finish on time.
Personnel required to finish the project on time (1-1/3)/(1/648×18) = 24 people.
Need to increase 24- 18=6 people.
4. Two people, Party A and Party B, process a batch of parts, with Party A processing 1.5 hours first, and then Party B processing. When the task is completed, Party A will complete five-eighths of this batch of parts. It is known that the efficiency ratio of Party A and Party B is 3:2. Q: How many hours does it take for Party A to process this batch of parts alone?
Solution: The working efficiency ratio of Party A and Party B is 3: 2.
That is, the ratio of workload is 3: 2.
B has completed 2/3 of A.
B Completed (1-5/8)=3/8.
Then both parties work together, and the completed workload is =(3/8)/(2/3)=9/ 16.
Therefore, it takes1.5/(5/8-9/16) =1.5/(1/6) = 24 hours.
9. For a batch of parts, if Party A and Party B work together for 5.5 days, it can exceed 0. 1 of the batch of parts. Now Party A works for 2 days, then Party A cooperates for 2 days, and finally Party B works for 4 days to complete the task. If Party B works alone, how many days can this batch of parts be completed?
Solution: treat all parts as a unit 1.
Then the sum of the work efficiency of Party A and Party B = (1+0.1)/5.5 =1/5.
The whole process is that A works 2+2=4 days.
B working 2+4=6 days.
It is equivalent to 4 days of cooperation between Party A and Party B, and 1/5×4=4/5 is completed.
Then B does it alone for 6-4=2 days 1-4/5= 1/5.
So it takes 2/( 1/5)= 10 days for B to complete it alone.
10, there is a project to be completed within the specified date. If Team A does it alone, it will be finished on schedule. If Team B does it alone, it will take more than 5 days to finish. Now Team A and Team B have been working together for three days, and the rest of the projects are completed by Team B alone as planned. How many days is the specified date?
Solution: 3 days of A is equivalent to 5 days of B.
The work efficiency ratio of Party A and Party B is 5: 3.
Then the ratio of completion time between Party A and Party B is 3: 5.
So it takes 3/5 time for A to complete.
So it takes 5/(1-3/5) = 5/(2/5) =12.5 days for B to complete it alone.
Specified time = 12.5-5=7.5 days.
1 1. A project will be completed in 20 days by team A and 30 days by team B. Now team B will finish it in five days, and the rest will be completed by team A and team B. How many days will it take?
Solution: B completed 5× 1/30= 1/6 in 5 days.
The work efficiency of Party A and Party B =1/20+1/30 =1/6.
Then (1-1/6)/(1/6) = (5/6)/(1/6) = 5 days.
12. It takes 15 days for Party A to complete a project, 15 days for Party B, and 20 days for Team C. The three teams work together, and Team A has left because of something. It took six days. How many days did Team A actually work?
Solution: the sum of the working efficiency of ethylene and propylene =115+1/20 = 7/60.
Do both B and C for 6 days, and finish 7/60×6=7/ 10.
A complete1-7/10 = 3/10.
Then A actually made it (3/10)/(110) = 3 days.
I'll send it to you if I think it's okay.