∴ non-p: x > 1 or x
Q: X again? -(2a+ 1)x+a(a+ 1)《0
∴ Non-question: X? -(2a+ 1)x+a(a+ 1)>0
Let f(x)= x? -(2a+ 1)x+a(a+ 1)
It has just been proved that f(x)>0 is enough.
Question: Necessary but not sufficient conditions for non-P and non-Q.
∴f( 1)>； 0
f( 1/2)>0
= > a> 1 or a