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High school math arrangement: two men and three women participate in an activity, two men do not appear next to each other, and one woman does not appear first. How many ways are there? ask
60 combinations.

The required arrangement is 5*4*3*2.

A girl has 4*3*2 for the first time.

When two men are adjacent, there are 3*2 and four adjacent positions, that is, 3*2*4, while the first woman has 2, and there are three adjacent positions between two men, that is, 2*3, and there are two adjacent positions between two men, so there is (3*2*4-2*3)*2.

Then * * * has: 5*4*3*2-4*3*2-(3*2*4-2*3)*2=60.