Symmetry axis =-b/2a=-2√3/3 divided by 2√3/3=- 1.
X=- 1 substitution
y=4√3/3
E(- 1,4√3/3)
2) Even AC because ∠AOC=90.
So AC goes through point O, so let's set the radius R.
-√3/3x? -2√3/3x+√3=0
x 1= 1 x2=-3
A(-3,0) C(0,√3)
R= 1/2AC
AC^2=AO^2+OC^2
AC=2√3
R=√3
S circle M =π* R2 = 3PI
3)