Symmetry axis =-b/2a=-2√3/3 divided by 2√3/3=- 1.

X=- 1 substitution

y=4√3/3

E(- 1，4√3/3)

2) Even AC because ∠AOC=90.

So AC goes through point O, so let's set the radius R.

-√3/3x？ -2√3/3x+√3=0

x 1= 1 x2=-3

A(-3，0) C(0，√3)

R= 1/2AC

AC^2=AO^2+OC^2

AC=2√3

R=√3

S circle M =π* R2 = 3PI

3)