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The first chapter of the second grade mathematics exercises.
As we all know, as shown in the figure, all the angles of hexagonal ABCDEF are equal. Please judge the size of AB+BC and DE+EF and explain the reasons.

A: AB+BC=DE+EF. Reason:

Solution: the extension line of AB, the reverse extension line of CD intersect G, and the extension line of DE/AF intersect H,

All the angles of a hexagon are equal,

∴∠a=∠abc=∠bcd=∠d=∠afe=∠def= 120,

∴∠GBC=∠BCG=∠HFE=∠HEF=60,

∴△BCD and△△△ Hef are equilateral triangles,

∴BC=BG,EF=EH,∠G=∠H═60,

∴∠A+∠G= 180,∠D+∠G= 180,

∴AG∥DH,AH∥GD,

∴ Quadrilateral AGDH is a parallelogram,

∴AG=DH,

∴AB+BC=DE+EF.