As we all know, as shown in the figure, all the angles of hexagonal ABCDEF are equal. Please judge the size of AB+BC and DE+EF and explain the reasons.

A: AB+BC=DE+EF. Reason:

Solution: the extension line of AB, the reverse extension line of CD intersect G, and the extension line of DE/AF intersect H,

All the angles of a hexagon are equal,

∴∠a=∠abc=∠bcd=∠d=∠afe=∠def= 120，

∴∠GBC=∠BCG=∠HFE=∠HEF=60，

∴△BCD and△△△ Hef are equilateral triangles,

∴BC=BG,EF=EH,∠G=∠H═60，

∴∠A+∠G= 180，∠D+∠G= 180，

∴AG∥DH,AH∥GD，

∴ Quadrilateral AGDH is a parallelogram,

∴AG=DH，

∴AB+BC=DE+EF.