Let the total number be x, then Y=(X+ 1) is divisible by 3, 5, 7, 9, y is divided by 1 1, and the remainder is 1. The least common multiple of 3, 5, 7 and 9 =5*7*9=3 153 15 divided by 1 1, and the remainder is 7. The problem is transformed into: find the integers A and B to make 7 * A- 1 = 165438. The number of jailers is: 315 * a-1= 2519. Considering that the least common multiple of 3,5,7,9, 1 1 is 3465, the final answer is: (25 19+.