(1) Yours is right. I won't repeat it, get m & gt-3.

There is something wrong with your formula.

It should be 2m- 1

Solve m

(1) and (2) intersect.

-3 & lt； M<- 1/2 or m>- 1

As for the equal sign, you should see clearly that there is no equal sign in A and there is an equal sign in B.

If 2m- 1=-2, there is no -2 in A and -2 in B, but it can't be handed in.

When 3m+2=5, the same is true!