Both groups have an a.
Therefore, in both cases, 1.a equals 1 ab=b a cannot equal 1 a=- 1 b=0.
2. Party A = Party B ab= 1, then A can only be equal to 1, so it is discarded.
So a=- 1 b=0.
Second, the same.
1.a-3=-3 a=0
2a- 1=- 1
Party A+1= 1 meets the requirements.
2.2a- 1=-3 a=- 1
a-3=-4
The square of a+1=2 is consistent.
3. Party A+1=-3 obviously does not meet the requirements.
So a=0 or-1.