Both groups have an a.

Therefore, in both cases, 1.a equals 1 ab=b a cannot equal 1 a=- 1 b=0.

2. Party A = Party B ab= 1, then A can only be equal to 1, so it is discarded.

So a=- 1 b=0.

Second, the same.

1.a-3=-3 a=0

2a- 1=- 1

Party A+1= 1 meets the requirements.

2.2a- 1=-3 a=- 1

a-3=-4

The square of a+1=2 is consistent.

3. Party A+1=-3 obviously does not meet the requirements.

So a=0 or-1.