Current location - Training Enrollment Network - Mathematics courses - 20 1 1 Who knows the detailed solution steps of the last question of Huzhou Mathematics 24? thank you
20 1 1 Who knows the detailed solution steps of the last question of Huzhou Mathematics 24? thank you
Have you figured it out? Connect MO? , ∠ mho = 90, so h is a point on a circle with a diameter of MO.

So where did the H point come from?

When point P approaches point C, the abscissa of point E is infinite, so ME is almost parallel to CB. At this time, point h almost coincides with point C.

At this time, just calculate the degree of H rotation. H rotation and ∠EMC complementary angle. Just ask ∠EMC.

When point P coincides with the origin, it is found that ∠EMC is equal to 135. You should know everything after that.