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Math problem: Give three different natural numbers at will, and one of them must have two numbers whose difference is even. Do you think it's right? Please provide a justification for the answer.
First of all, the three numbers have the following situations:

One: three odd numbers, in which the difference between two numbers is even.

Two: three even numbers, in which the difference between two numbers is even.

Three: 1 The difference between odd 2 and even 2 is even.

Four: 2 odd 1 even 2 odd difference is even.

So among these three numbers, the difference between two numbers must be 1 even number, which is correct.