Get rid of the bracket problem 10 in the basic training of mathematics in the first grade.

A(a-b)= 18 can be obtained from the square of A-AB = 18.

a-b= 18/a

B(a-b)=- 12 can be obtained from the square of ab-b.

a-b=- 12/b

Then a-b= 18/a and a-b=- 12/b, 18/a=- 12/b can be converted into a=-2 3b.

B =-2a/3

Bring a=-2 3b into the square of A-AB = 18.

The square of (-3b)-(3b) = 18.

9/4 square +3/2 square = 18.

The square of b = 24/5.

Bring b=-3 2a into ab-b square =- 12.

-2a-(-2a) =- 12 squared.

-2/3a squared -4/9a squared =- 12

The square of a = 54/5.

Then the square of A -AB = 18, and the square of A = 54 gives 5.

You can get the square of ab=a-18.

= 54/5 squared-18

=-36/5

Then the square of A-the square of B = 54/5-24/5 = 6.

The square of a of 2ab+b = 54-2 (-36)+24= 1 and 1.