1.34 people go for a spring outing, * * * collects money from 80 yuan, and Xiaoming goes to buy snacks, each person needs 1 bag. There are two kinds of snacks known, one from 2 yuan and the other from 3 yuan. How many bags can I buy for 3 yuan at most?

Collect 3 yuan for snacks and buy X packages.

According to the meaning of the question:

3X+2(34-X)≤80

So x+68 ≤ 80

So X≤ 12

So the maximum value of x is 12.

So you can only buy 12 packs of snacks for 3 yuan at most.

2. if the solution of inequality set 2x-a < 1x-2b > 3 is-1 < x < 1, find the value of (A+ 1) multiplied by (B+ 1).

Solution.

2X-A2B+3

From the solution to-1 < x < 1, we get

(A+ 1)/2= 1

2B+3=- 1

Get a = 1 and b =-2.

Therefore, (a+1)× (b+1) = 2× (-1) =-2.

Give some children a box of apples. If you give four apples to each child, there are eight apples left. If you give eight apples to each child and less than six apples to one child, how many children are there? How many apples are there in the box?

Solutions;

Suppose an apple has m children, x children, and those who don't get 8 apples get y children.

M=5X+6 5438+02 M=8(X-6 5438+0)+Y is 8(X- 1)+Y=5X+ 12, 3X=20-Y X can be 65.

Y is 2 5, so there are two possibilities, namely

The child has 5 apples and 37 apples.

The child has 6 apples and 42 apples.

4. If the inequality about x is 2x-4- 1.

Therefore, the range of values is x>- 1 and x is not equal to 0.

10. the solution set of inequality group X > 2m+ 1 and X > m+2 is X >- 1, so what is the value of m?

The solution sets of inequality groups x > 2m+ 1 and x > m+2 are x >- 1.

If 2m+1>; M+2, m>- 1, then 2m+ 1=- 1, does not meet the problem.

If m+2 >; 2m+ 1，m