Let the speed of the bus be V and the speed of Xiao Wang be U. Because there is a bus every X minutes, the distance between two cars traveling in the same direction is vx, that is, VX/(V-U) = 6 and VX/(V+U) = 3.

The sum of the two formulas is 2v/vx= 1/2.

Then x=4.

2. Let three sides be A, B and C, and the corresponding angles are A, B, C, B = 2A, and C = π-3A.

According to sine theorem, a/sinA=b/sinB=c/sinC,

Get a/sinA=b/sin2A=c/sin3A.

a/sina=b/2sinacosa=c/(3sina-4sina^2)

Then 2cosa = b/a, 4sina2 = 3-c/a.

Then 4cosa 2+4cina 2 = 3+(b 2-AC)/a 2 = 4.

(b^2-ac)/a^2= 1

B = 6，A = 4，C = 5。