1, 16 Let the length, width and height of a cuboid be x, y, z 2 (xy+yz+zx) = 224x = y z = 3x.

2, 1 bit, except 13 remainder 2.

2 digits divided by13,9

3 digits except 13 1

Four digits except 13 1 1

5 digits except 13+5

6 bits divided by 13+0

Start the cycle

7 digits except 13 remainder 2

8 digits except 13+9

500/6 Yu 2

The remainder is 9.

This number is divisible by 48, and the maximum three digits are 960.

The sum of the numbers divisible by 2,3 in 4,3-36 is 2 * (1+2+4+5+7+8+10+1+/kloc-0+)

3*( 1+3+5+7+9+ 1 1+ 13+ 15+ 17+ 19+2 1)

1/2*( 1+36)*36 Subtract the above sum and divide by 36.

5 Cyclic decimals 307692 and 27 2000/6=333*6+2 333*27+3 = 8994.

6 1.25 5*5*5/ 100