Root number (X+5)=4- root number (X-3)

Double-sided square:

X+5= 16-8 radical (X-3)+X-3

According to the project:

Root number (X-3)= 1

X-3= 1

X=4

X=4 is the root of the equation.

2. It is known that the root number of the equation about X (m-2x)+m+x=3 is x= 1. Find m.

Substitute X= 1 into the equation:

Root number (M-2)+M+ 1=3

Root number (M-2)= 2m

Square:

M-2=4-4M+M^2

M^2-5M+6=0

(M-2)(M-3)=0

M 1=2，M2=3。

Also: root number (m-2) = 2-m >; =0, that is, m

So: M=2