Root number (X+5)=4- root number (X-3)
Double-sided square:
X+5= 16-8 radical (X-3)+X-3
According to the project:
Root number (X-3)= 1
X-3= 1
X=4
X=4 is the root of the equation.
2. It is known that the root number of the equation about X (m-2x)+m+x=3 is x= 1. Find m.
Substitute X= 1 into the equation:
Root number (M-2)+M+ 1=3
Root number (M-2)= 2m
Square:
M-2=4-4M+M^2
M^2-5M+6=0
(M-2)(M-3)=0
M 1=2,M2=3。
Also: root number (m-2) = 2-m >; =0, that is, m
So: M=2