Answer: (1) According to the known conditions, the total length of ACBEA is 400 meters, and the total length of ACB is 200 meters. It takes 24 seconds for a speed 100 meter and 2 1 second for b speed 100 meter, so it takes 48 seconds for A to pass through ACB and 42 seconds for B to pass through ACB. That is to say, if B passes through point A no later than 6 seconds, he can catch up with A in this lap. Let's look at the time series table of A and B passing through point A..
First lap, second lap, third lap, fourth lap, fifth lap, sixth lap.
A (275m per lap) 0 66 132 198 264 330
B (400 meters per lap) 0 84 168 252 336 420
From the above analysis, when B starts to run the fifth lap, A starts to run the sixth lap, and B passes through point A no later than 6 seconds, which shows that B will meet A for the first time when running the fifth lap.
(2) It takes 66 seconds for A to run a lap and 84 seconds for B to run a lap, and their least common multiple is 924, so after 924 seconds, that is, 15 minutes and 24 seconds, A and B return to point A at the same time for the first time.
Answer: (1) B met A for the first time on the fifth lap. 924 seconds after departure, Party A and Party B meet again at point A..
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