What else can we do?

First of all, let me say

This is your unpunctuality.

I waited all night yesterday.

This question is ok, but as the finale, it is not difficult.

I'll write the specific process.

You can ask me if you don't understand.

First, talk about ideas.

Because one of the inertia thinking of doing this kind of problem is

Seeing that the topic condition n is a positive integer, I thought of discussing parity in connection with two problems.

Then I personally feel that there is already a small proof for reference because of 2) Q.

The proof method is as follows:

Let y2 = x2 n+a/x2 n when n is an even number.

y 1=x 1^n+a/x 1^2

And then simplified to y2-y1= (x2 n-x1n) (1-a/x1n * x2 n).

Obviously, when the root number of a is 2n.

And y2>y 1,

Function increment

That is, when x is greater than the root number 2n of a, it increases.

Similarly, it decreases by (0, the root of a is 2n power).

Because n is even, it is an even function. ...

So according to the symmetry, we can get two intervals.

Similarly, when n is an odd city,

The original function is odd function.

Then the monotone interval is easy to know in the same way.

It's actually quite simple.

It's just harder.

Then you should be able to.

Is to do it with mean inequality

So 1 is the minimum.

1/2

At 2 o'clock at most.

Get two solutions ....

You can ask me if you don't understand.

But don't blame yourself on others.

If I beg someone,

I can't play big cards

Let others take the initiative to find me.

Because the person who helps you has his own things to do.

Not so free.

:)

I wish the college entrance examination success.