A similar math problem in the second day of junior high school

1, rectangular ABCD is similar to rectangular BCFE.

Therefore, AB/BC=AD/BE.

ADFE is square.

Therefore, BC = AD = AE.

Therefore, AB/AE=AE/BE.

Therefore, point E is the golden section point of AB surface.

2. The aspect ratio of the golden rectangle is the golden ratio.

According to 1, point e is the golden section point of AB.

AB/AE = AE/BE = golden ratio

Because AB/BC=AD/BE, ADFE is a square, and AD = BC = AE.

Therefore, BC/BE = AB/AE = golden ratio.

Therefore, the rectangle BCEF is a golden rectangle.