If the speed of the car is increased by 20%, it can arrive 1 hour earlier than the original time. If you drive at the original speed120km and then increase the speed by 25%, you can arrive 40 minutes earlier. How many kilometers is it between A and B?

40 minutes =2/3 hours

Scheduled time1÷1-1(1+20%) = 6 hours.

The original speed is120-120/(1+25%) ÷ 6-2/3-6/(1+25%) = 24 ÷ 8//kloc-0.

The distance between Party A and Party B is 45× 6 = 270km.