b^2-b-3=0 a^2-a-3=0
So a 2 = a+3, b 2-b = 3.
The original formula = 2a (a+3)+3+3a2-11a+5.
=2a^2+6a+3+3a^2- 1 1a+5
=5a^2-5a+8
=5(a^2-a)+8
=5*3+8
=23
I hope I can help you and adopt it. I wish you progress in your study.