Solution: Because A and B are two roots of the equation, A+B = 1 and AB =-3.

b^2-b-3=0 a^2-a-3=0

So a 2 = a+3, b 2-b = 3.

The original formula = 2a (a+3)+3+3a2-11a+5.

=2a^2+6a+3+3a^2- 1 1a+5

=5a^2-5a+8

=5(a^2-a)+8

=5*3+8

=23

I hope I can help you and adopt it. I wish you progress in your study.