Let the coordinates of these two points be (x 1, y 1)(x2, y2) respectively.

1, oblique type

Find the slope: k=(y2-y 1)/(x2-x 1)

The linear equation y-y 1=k(x-x 1)

Then substitute k into y-y 1=k(x-x 1) to get the linear equation.

2, two-point type

Because (x 1, y 1), (x2, y2)

So the linear equation is: (x-x1)/(x2-x1) = (y-y1)/(y2-y1).

Extended data:

Other linear equation expressions:

1, intersection: f 1(x, y) *m+f2(x, y)=0 is applicable to any straight line.

A straight line passing through the intersection of the straight line f 1(x, y)=0 and the straight line f2(x, y)=0.

2. The point leveling formula: f(x, y) -f(x0, y0)=0 is applicable to any straight line.

A straight line passing through the point (x0, y0) and parallel to the straight line f(x, y)=0.

3. The normal formula: X COS α+YSIN α-P = 0 is suitable for straight lines that are not parallel to the coordinate axis.

A vertical line segment that passes through the origin and becomes a straight line. The inclination of the straight line where the vertical line segment is located is α, and p is the length of the line segment.

4. The point-by-point formula: (x-x0)/u=(y-y0)/v (u≠0, v≠0) is applicable to any straight line.

A straight line passing through point (x0, y0) has a direction vector of (u, v).

5. Normal formula: a(x-x0)+b(y-y0)=0 is applicable to any straight line.

A straight line passing through the point (x0, y0) and perpendicular to the vector (a, b).