The linear function of (1) is y=x+b, and the inverse proportional function is y= 1/x, so the simultaneous formula shows that the intersection point is A(-b+√b? +4/2， 1/-b+√b？ +4/2)，B(-b-√b？ +4/2， 1/-b-√b？ +4/2)。

(2) The value of the original function is smaller than that of the inverse proportional function, and the range is between AB points, so it is (-b-√b? +4/2，-b+√b？ +4/2)。

Just bring the test paper directly when you see it. If you don't understand, ask me. I will be more specific. I wish you progress in your study!