Pirates are divided into gold coins:

In the United States, it is said that the average annual salary of people who can answer this question within 20 minutes is more than 80,000 dollars.

After five pirates robbed 100 gold coins, they discussed how to distribute them fairly. Their agreed distribution principle is: (1) draw lots to determine everyone's distribution sequence number (1, 2, 3, 4, 5); (2) Pirates who draw lots. 1 Propose a distribution plan, and then five people will vote. If the plan is approved by more than half of the people, it will be distributed according to his plan, otherwise it will be thrown into the sea to feed sharks. (3) If not. 1 cast into the sea, No.2 puts forward the distribution plan, and then there are 4 people left to vote, if and only if it exceeds. 4 and so on. Assuming that every pirate is extremely intelligent and rational, they can make strict logical reasoning and rationally judge their own gains and losses, that is, they can get the most gold coins on the premise of saving their lives. At the same time, assuming that the results of each round of voting can be implemented smoothly, what distribution scheme should the pirates who have drawn 1 put forward to avoid being thrown into the sea and get more gold coins?

Thinking of solving problems 1:

Let's talk about Pirate No.5 first, because he is the safest and has no risk of being thrown into the sea, so his strategy is also the simplest, that is, if all the people in front are dead, then he can get 100 gold coins by himself. Next, look at No.4, and his chances of survival depend entirely on the existence of others in front, because if all the pirates from 1 to No.3 feed sharks, No matter what distribution scheme No.4 proposes, No.5 will definitely vote against it and let No.4 feed sharks to keep all the gold coins. Even if No.4 pleases No.5 to save his life and puts forward a plan like (0, 100) to let No.5 monopolize the gold coins, No.5 may think it is dangerous to keep No.4 and vote against it, so that he can feed the sharks. Therefore, rational No.4 should not take such a risk and pin his hope of survival on the random selection of No.5. Only by supporting No.3 can he absolutely guarantee his life. Look at number three. After the above logical reasoning, he will put forward such a distribution scheme (100,0,0), because he knows that No.4 will unconditionally support him and vote for him, so adding his own 1 vote will make him safely get100 gold coins. But player 2 also knows the allocation scheme of player 3 through reasoning, so he will propose a scheme of (98,0, 1, 1). Because this scheme is relative to the distribution scheme of No.3, No.4 and No.5 can get at least 1 gold coins. Rational No.4 and No.5 will naturally think that this plan is more beneficial to them, support No.2, and don't want No.2 to go out, so No.3 will be allocated. So number two can get 98 gold coins with a fart. Unfortunately, One Pirate 1 is not a fuel-efficient lamp. After some reasoning, he also understands the distribution scheme of No.2. The strategy he will take is to give up No.2 and give No.3 1 gold coins, and at the same time give No.4 or No.5 2 gold coins, that is, to propose (97,0, 1 2,0) or (97,0). Because the distribution scheme of 1 can get more benefits for No.3 and No.4 or No.5 than No.2, then they will vote for 1, plus 1' s own 1 ticket, and 97 gold coins can easily fall into the pocket of 1.

Puzzle 2

8+7=62

5+3=5

12+8=23

50+9=54

1 1* 1=55

0-9= 1

The numbers in these formulas are all passwords, and each number represents a different number, so these formulas should be established at the same time.

0=5 1=3 2=4 3=0 4=7

5=9 6= 1 7=8 8=6 9=2

These two questions are enough weight.