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Who knows the speed of reviewing the answers to the seventh chapter of seventh grade mathematics in People's Education Edition?
2. (1) 40 (2) 70 (3) 60 (4)100 (5) 70 degrees

3, 7 sides inner angle and 900 degrees, outer angle and 360 degrees; 17 polygon, 360 degrees; 25 sides, 360 degrees.

4, 5 diagonals, 6 triangles, equal relationship

5,7 polygons, (900/7) degrees

6. Because angle 1= angle A+ 10, angle B=42, angle A+ angle 1,+angle B= 180, angle A=64, and angle A= angle ACD.

7. Let angle A=X, because angle C= angle ABC=2 angle A, angle C= angle ABC=2X, and because BD is perpendicular to AC, angle ABD=90-X, angle CBD=90-2X, angle ABD+ angle CBD= angle ABC, that is, (90-x)+(90-2x).

8. Because the angle BAC = 50, the angle C = 70 and the angle ABC = 60. Because AE and BF are bisectors, angle ABF-= 1/2, angle ABC = 30, angle BAE= 1/2, angle BAC = 25, so angle BOA = 65438+. Angle DAC=90- Angle C=20 degrees because AD is high.

9. Angle 1+ angle 2+ angle 3+ angle 4= 180- angle A=80 degrees, and because angle 1= angle 2, angle 3= angle 4, angle 2+ angle 4= angle 1+ angle 3 = 6544.

10, (1) BEcause be and CF are bisectors, angle ABE= angle EBC= 1/2 angle ABC, angle ACF= angle FCB= 1/2 angle ACB.

Angle BGC= 180- angle EBC- angle FCB= 180- (angle EBC+ angle FCB) = 180- (angle ABC+0/2+0/2+ACB) = 18.

(2) because angle ABC+ angle ACB= 180- angle a, because be and CF are bisectors, angle EBC+ angle FCB= 1/2 (angle ABC+ angle ACB)= 1/2( 180-)

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