At right angles △BDE, ∵∠b = 60°, ∴∠ Bed = 30,
∴BE=2x,∴CE=2-2x，
Similarly: cf = 1-x, af = 1+x,
Point f is the advertising vertical line, and point g is the vertical foot.
So ∠ AFG = 30, ∴AG=? ﹙ 1+x﹚，
∴:fg =√3/2√ 1+x√ from Pythagorean theorem
∴△ADF area = ××-2-x × √ 3/2 √1+X.
=﹙√3/4﹚﹙2+x-x？ ﹚,
∴ Quadrilateral DBCF area =△ABC area -△ ADF area
=﹙√3/4﹚×2? -﹙√3/4﹚﹙2+x-x？ ﹚
=﹙√3/4﹚﹙2-x+x？ ﹚,
When x=? When point e is located at the midpoint of BC,
△ADF area ∶ quadrilateral BCFD area =9∶7,
When x=? (that is, when point E is at the quartering point of BC), △ADF area ∶ quadrilateral BCFD area =35∶29.
……
When point E is not fixed, their area ratio is not fixed.
This question can't find their area ratio.