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Pythagorean Theorem of Mathematics Problems in Grade Two in Shanghai
The area of triangle ADE is1/2 * de * ad =1/2 * (1/2ae) * (√ 3/2ae).

The area of triangle ABC is1/2 * BC * AC =1/2 * (√ 3/3ac) * AC.

Their area ratio is 2.

AE and AC can be obtained

proportion

Then the ratio of CE to AE length is derived.

The idea is to use AE to represent the area of a small triangle.

The area of a big triangle is represented by AC.

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