Circle m and circle C2 are tangent to Q.

MC 1+MC2=C 1T+QC2=4

oblong

a=2 c= 1

X 2/4+Y 2/3 =1demarcation point (2,0)

The angle c 1pc2 = 90 degrees, so the trajectory of p.

x^2+y^2= 1

PEmax is PE divided by o (0 0,0).

1+5^0.5

Using polar coordinate equation

P (meat) = EP/( 1- ecological cost)

e=c/a= 1/2

p=a^2/c-c=3

ac=ep/( 1-ecost)+ep/( 1+ecost)=2ep/( 1-(ecost)^2)

BD=2ep/( 1-(esint)^2)

The area of 2*ABCD is s = AC * BD = (2ep) 2/(1-E2+E4 (cost * Sint) 2) min.

So the cost *sint is very large.

So 2cost*sint is very big.

Sin2t is large = 1

So t = 45 degrees.

Substitute for s