Let -x+ 1=t, then x+1= 2-t.

So f(t)=-f(2-t)

Because t+2-t=2, that is, when the midpoint of the abscissa is 1,

F(t)=-f(2-t), the ordinate is reciprocal, that is, it adds up to 0, and the midpoint of the ordinate is 0.

The midpoint of the horizontal and vertical coordinates is (1, 0).

So the symmetry point is (1, 0)