Then the attenuation equation is:? 137N→? 136C+? 0 1e
(2) According to the left-handed rule and the relationship between force and motion, the trajectory diagram is shown in the figure.
(3) According to the law of conservation of momentum, mcvc=meve is obtained.
Is the orbital radius of recoil nucleus or carbon nucleus R2?
R2=mcvc6eB
Positron r = meveeb
So what? r=3R
As can be seen from the figure, the coordinates x and y of the position p where positrons are emitted from the magnetic field satisfy:
According to the geometric relationship, r2=x2+(r-y)2?
R2=x2+y2
The result of the solution is x = 356 r.
y=R6
A: (1) The decay equation is:? 137N→? 136C+? 0 1e;
(2) Draw the trajectory diagram of positron and recoil nucleus as shown on the right;
(3) The coordinates (356R, R6) of the positron leaving the magnetic field.