The landlord must be waiting for me, and I will give him a satisfactory answer! (I'm drawing for the landlord)
As shown in the figure, if APEB is a parallelogram, then ∠ 1=∠5, and it is also known that ∠ 1=∠2, ∠ 2 = ∠ 5, ∴P, c, e, b.
Even EC and CDPE are parallelograms, ∫ad‖BC, PD‖EC, ∴∠ 4 = ∠ 7-(2)?
∵APEB is a parallelogram, ∴AB‖PE, ∴∠3=∠6,-(3)?
From (1)(2)(3), we know that ∠3=∠4, that is ∠ABP=∠ADP?
If you haven't studied the four-point * * * Garden, you can prove that △ POC ∽ EOB → BO/PO = OE/OC →△ POB ∽ EOC → ∠ 6 = ∠ 7?
If the landlord wants to use a similar certificate, let me know and I will send it to the landlord!