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Mathematical problems (junior high school) (about motivation)
( 1)≈APO+∠QPE = 180-90 = 90,∠APO+∠PAO=90

∴∠PAO=∠QPE

∫ rectangular AOEC

∴∠AOE=∠QEP

∴△AOP∽△PEQ

∴ao/pb=op/qb,3/x=(4-x)/(3-y)y = 1/3(x? -4X+9) (0≤X≤4)

(2) The coordinates of ∵ C are (4,3), ∴OB=4, BC=3, ∴ 5/3≤Y≤3, that is, Q cannot reach C.

According to the quadratic function Y= 1/3(X? -4X+9) (0≤X≤4), that is, Y= 1/3(X-2)? +5/3 (0 ≤ x ≤ 4) can get the vertex coordinates of (2,5/3). When X=2, y takes the minimum value of 5/3.